Exception handling to detect input String vs. Integer

Exception handling to detect input String vs. Integer

The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age.

Ex: If the input is:

Lee 18

Lua 21

Mary Beth 19

Stu 33

-1

then the output is:

Lee 19

Lua 22

Mary 0

Stu 34

// Use the following code:

import java.util.Scanner;

import java.util.InputMismatchException;

public class NameAgeChecker {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

String inputName;

int age;

inputName = scnr.next();

while (!inputName.equals(“-1″)) {

// FIXME: The following line will throw an InputMismatchException.

// Insert a try/catch statement to catch the exception.

age = scnr.nextInt();

System.out.println(inputName + ” ” + (age + 1));

inputName = scnr.next();

}

}

}